Following figures are given in the question.

- V ⇒ 3V (Volts)
- I ⇒ 2A (Ampere)

The **total resistance** in a series circuit is equal to ⇒ the sum of the individual resistances:

RN(series) = R_{1}+ R_{2}+ R_{3}+…+ R_{N}

**Series:** A number of things that follow on one after the other or are connected one after the other.**Resistance:** The opposition to the passage of an electric current through that element.

Suppose, n resistances of 6 ohm are connected in parallel and the resultant resistance=R

By ohm's law V = IR

- 3 = 2 x 6/n
- 3 = 12 / n
- 3 x n = 12
- n = 12 / 3
- n = 4

Hence, 4 bulbs are connected in parallel.

Solution is based on