How many bulbs of resistance 6 ohms should be joined in parallel to draw current of 2 amperes from battery 3 volts

Question

plz tell in brief i have alredy solution but I am unable to get it

Answer 1

Following figures are given in the question.

• V ⇒ 3V (Volts)
• I ⇒ 2A (Ampere)

The total resistance in a series circuit is equal to ⇒ the sum of the individual resistances: 

RN(series) = R₁+ R₂+ R₃+…+ R_N

• Series: A number of things that follow on one after the other or are connected one after the other.
• Resistance: The opposition to the passage of an electric current through that element.

Suppose, n resistances of 6 ohm are connected in parallel and the resultant resistance=R

• 1/R = n/6
• R = 6/n

By ohm's law V = IR

• 3 = 2 x 6/n
• 3 = 12 / n
• 3 x n = 12
• n = 12 / 3
• n = 4

Hence, 4 bulbs are connected in parallel.

Solution is based on 

• Jyoti Pant from meritnation.com
• Lumen Learning