Following figures are given in the question.
- V ⇒ 3V (Volts)
- I ⇒ 2A (Ampere)
The total resistance in a series circuit is equal to ⇒ the sum of the individual resistances:
RN(series) = R1+ R2+ R3+…+ RN
- Series: A number of things that follow on one after the other or are connected one after the other.
- Resistance: The opposition to the passage of an electric current through that element.
Suppose, n resistances of 6 ohm are connected in parallel and the resultant resistance=R
By ohm's law V = IR
- 3 = 2 x 6/n
- 3 = 12 / n
- 3 x n = 12
- n = 12 / 3
- n = 4
Hence, 4 bulbs are connected in parallel.
Solution is based on