2x2πrT = PA = Pπr2 giving:
Excess pressure in a soap bubble (P) = 4T/r.
A bubble of air within a liquid has only one liquid-air surface and the excess pressure within such a bubble is simply:
Excess pressure in an air bubble (P) = 2T/r.
Both these formulae show that the excess pressure within a small bubble is greater than that within a larger bubble.
https://www.youtube.com/watch?v=95Jomq0lvBg
(source: schoolphysics, Edupoint)
