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Radius_3.5
When sphere is placed in cylinder jar the water just cover the sphere

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Total surface area of cylinder

Suppose a cylinder of radius r and height h. The total surface area (TSA) involves the area of the circular top and base, as well as the curved surface area (CSA).

Area of a CylinderArea of a Cylinder
Now, the length of the rectangle
= Perimeter of the base
= 2πr

The Width of the rectangle
= Heigh of the Cylinder
= h

∴ TSA = Area of the Lid + Area of the Base + Curved Surface Area
πr2 + πr2 + 2πrh
2πr2 + 2πrh
= 2πr (r+h)

The total surface area (TSA) of a cylinder with radius and height h is given by

2πr (r+h)

The depth of water in the can before the sphere was put.

Volume of the can up to the length sphere is placed – Volume of the sphere = Volume of the can up to the depth of water that was in the can before the sphere was placed inside

πr²h – (4/3)πr³ =πr²H, where ‘h’ is the height of the can up to sphere is placed i.e. 2r = 2*3.5 = 7; r = 3.5 and H = depth of the water in the can before the sphere was put in (to find)

Now dividing both sides of the above equation by πr²
h – (4/3)r = H
=> 7 – (4/3)*3.5 = H
=> 7/3 = H

So 7/3 cm is the answer

(Source: mathsteachersscexamforum)

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