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Best answer
560

Resolve it into (1+a)(1+b)(1+c)=1001
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Adding one on both side
a + b + c + ab + bc +ac + abc +1 = 2000 + 1
Using identity
(a + b + c + ab + bc + ac +abc + 1) =  
(1+ a) (1+ b) (1+c)
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