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A body starts from rest. What is the ratio of the distance travelled by the body during the 4th and 33rd second (Kindly solve step by step)

1 Answer

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answered by (8.3k points)

The formula is 

Sn= u+a/2(2n-1)

For t=n=3

S3= 0+10/2(5)

S3= 50/2 m

Similarly,

S4= 0+10/2(7)

S4= 70/2m

S3/S4= 50/2×2/50

S3:S4= 5:7

[source: brain.ly]

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