0 votes
asked by (160 points)


explain me few steps in the above link in a given solution

how the two zeroes are the zeroes of a quadratic equation


So the other two zeros are just the zeros of a quadratic in standard form:

please give me a detailed explanation of the steps given in the problem

Request: those who know only answer this.others please leave it blank

1 Answer

+1 vote
answered by (260 points)
If X is one of the zero of the equation then

a*0^3+ b*0^2+c*0+d=0


Gives d=0

So our final equation is


Take X common and transpose it



Now sum of the roots will be equal to  -b/a

And product of root will be c/a